Cos^2(2x)+2cos(x)+1=0

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Solution for Cos^2(2x)+2cos(x)+1=0 equation: 


Simplifying
Cos2(2x) + 2cos(x) + 1 = 0

Remove parenthesis around (2x)
os2C * 2x + 2cos(x) + 1 = 0

Reorder the terms for easier multiplication:
2os2C * x + 2cos(x) + 1 = 0

Multiply os2C * x
2os2xC + 2cos(x) + 1 = 0

Multiply cos * x
2os2xC + 2cosx + 1 = 0

Reorder the terms:
1 + 2cosx + 2os2xC = 0

Solving
1 + 2cosx + 2os2xC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2cosx + -1 + 2os2xC = 0 + -1

Reorder the terms:
1 + -1 + 2cosx + 2os2xC = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2cosx + 2os2xC = 0 + -1
2cosx + 2os2xC = 0 + -1

Combine like terms: 0 + -1 = -1
2cosx + 2os2xC = -1

Add '-2os2xC' to each side of the equation.
2cosx + 2os2xC + -2os2xC = -1 + -2os2xC

Combine like terms: 2os2xC + -2os2xC = 0
2cosx + 0 = -1 + -2os2xC
2cosx = -1 + -2os2xC

Divide each side by '2osx'.
c = -0.5o-1s-1x-1 + -1sC

Simplifying
c = -0.5o-1s-1x-1 + -1sC

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